There is no set of data that satisfies this condition: median > mode > mean > range.
The inquiry starts with students trying to understand the statement and, particularly, the constraint placed on the data set. Questions and comments that have arisen in the classroom are:  What do median, mode, mean, and range mean?
 What is a set of data?
 Why are there ‘greater than’ signs in the sentence?
 What does it all mean?
 How many numbers are there in a set of data?
 Do the median, mode, mean, and range have to be in that order?
 If the mean is higher than the mode, you have to start with the mean, then work out the mode.
 It must be possible.
 When we tried this, it worked for the median and mode, but went wrong on the mean.
 You can’t do it because the range is too small.
The prompt leads students into trying to construct sets of data that fulfil a certain condition. The teacher might orchestrate a discussion on how many numbers are appropriate in the data set and guide students towards using five or seven to simplify the start of the inquiry. If students are unfamiliar with the terms in the prompt, or need to revise them, they have in the past chosen a regulatory card that gives them time to practice finding the median and mode and calculating the mean and range before exploring the statement itself. However, it is possible to develop fluency in these procedures during the inquiry. In the search for a set of data described in the prompt, students begin to create sets that satisfy different inequalities. So, for example, students found this set that has mode > mean > range > median: Thus, a period of exploration can lead to a question about how many permutations of median, mode, mean, and range exist. In one inquiry, a group of students found the 24 permutations and The 'block' that starts with median median  mean  mode  range  median  mean  range  mode  median  mode  mean  range  median  mode  range  mean  median  range  mode  mean  median  range  mean  mode 
explained the result by using four ‘blocks’ based on the one they demonstrated to the class, which started with the median (see box). Another class working collectively found that, along with the constraint in the prompt, there are four other permutations for which it is impossible to create a data set:
Median > mode > range > mean Median > range > mode > mean Mean > mode > median > range Mean > mode > range > median This final result, if confirmed by other classes, leads onto other questions: Why are the five permutations impossible to achieve? Do they have something in common? Do they remain impossible to create if we use more numbers in the data set?
Update James Handscombe (Principal of Harris Westminster Sixth Form) has found a counterexample to the proposition in the prompt:
6 23 23 24 25 26 27 median 24 > mode 23 > mean 22 > range 21 James is confident that a data set of seven numbers exists for each of the 24 permutations. One question that follows concerns the smallest set of data that satisfies all the permutations  is it 7, 6, or 5 numbers?
You can follow James on twitter @JamesHandscombe
Resources Prompt sheet Promethean flipchart download Smartboard notebook download
Venn diagrams and the prompt Craig Barton (the TES adviser for secondary maths) has created tasks involving Venn diagrams and a wide selection of mathematical topics. The one for averages and range would make an effective means of assessing students' conceptual understanding that develops from the prompt. The task builds up to diagrams that require students to place numbers in three sets in such a way as to satisfy the constraints. You can follow Craig on twitter @tesMaths. A full list of the excellent Venn diagram tasks can be viewed here.
The prompt as a problem Two months after the averages inquiry was posted on the site, NRICH published Unequal Averages – a problem solving task for students based on the wellestablished “M, M, and M” problem. While the task is similar to the inquiry presented on this page, the differences reflect the distinction between problem solving and inquiry. Problem solving has a predetermined beginning (the question) and end (the solution). In the NRICH activity, the set of inequalities is defined and so is the size of the sets to be used (four, five, and six numbers). It is also clear that the problem setter knows the solutions, including those inequalities that cannot be satisfied. The problem solver is left with an 'open middle' in which to explain how we can arrive at the required endpoint from the given starting point. In contrast, an inquiry has the potential to have an open beginning, middle, and end. This is more motivational for students, as well as giving them the opportunity to pose mathematical questions and determine appropriate solution sets. The NRICH activity does, however, suggest one way to run a structured inquiry. The teacher could restrict the prompt to the three averages and limit the size of the set of numbers in the initial inquiry.
 Classroom inquiry These are the initial questions and observations of a year 9 (grade 8) class about the prompt: When invited to decide on the direction of the inquiry by selecting a regulatory card, the majority of students opted to "find more examples". The first lesson ended with one student presenting a set of data that satisfies the condition, although he used nine numbers instead of the seven agreed upon by the class: 31 32 53 53 56 57 58 59 60 median 56 > mode 53 > mean 51 > range 29 In the second lesson of the inquiry, students established four aims of their own:  Find sets of four, five, six, and seven numbers for which mean = median = mode = range.
 Find sets of five numbers that satisfy inequalities involving permutations of mean, median, and mode only.
 Find sets of seven numbers that satisfy inequalities involving permutations of mean, median, mode, and range.
 Find a set of numbers that satisfy the same permutation of mean, median, mode and range as in the prompt, but with the inequality reversed to "less than".
After selecting an aim, the students explored in pairs or groups before explaining their findings to the rest of the class.
Constructing an explanation The inquiry can lead to some ideas that students find difficult to explain. Why is it that they cannot create a data set that fulfils the inequality in the prompt? In one discussion, the teacher and class tried to construct an explanation by focusing on one case. They used seven positive whole numbers in the data set. The class also tried to make as many of the median, mode, mean, and range as possible positive whole numbers. Start with the median, let's say five.  __ __ __ 5 __ __ __  The mode has to be lower. We could arrange the numbers (with the mode shown by *) like this:  * * __ 5 __ __ __  Or like this:  __ * * 5 __ __ __  Or this:  * * * 5 __ __ __  If the mode is three, then the range is two. However, a contradiction arises because then the mode will become five when we fill in the remaining places.  3 3 __ 5 __ __ 5  So we make the mode four, and the range three. However, again we reach a contradiction because whether we use fives or sixes to fill the final two places the mode is not four (or at least not on its own).  3 4 4 5 __ __ 6  So, we make all three numbers less than the median four. The greatest value is then seven and the mean must be below four, but above three. This is not possible whatever numbers we decide upon to fill the last two places and we have our final contradiction.  4 4 4 5 __ __ 7  This did not constitute a proof of impossibility, even if we have exhausted all the possibilities in this one case. The class decided to inquire into whether changing the assumptions at the beginning  that is, only positive whole numbers in the data set, aiming at positive whole numbers for the median, mode, mean and range, using seven numbers, and starting with five as the median  led to a different outcome. Students chose one assumption to disregard. However, they could still not create a set of data to meet the conditions in the prompt. The class concluded that it is impossible.
